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Here's a solution for Range Sum Query using Segment Tree:

Approach:

• Build a binary tree where each node stores sum of its range

• Leaf nodes represent individual array elements

• Internal nodes store sum of their children's ranges

Time: O(log n) query/update | Space: O(n)

class SegmentTree:
    def __init__(self, arr):
        self.n = len(arr)
        self.tree = [0] * (4 * self.n)
        self.build(arr, 1, 0, self.n - 1)
    
    def build(self, arr, node, start, end):
        if start == end:
            self.tree[node] = arr[start]
        else:
            mid = (start + end) // 2
            self.build(arr, 2*node, start, mid)
            self.build(arr, 2*node+1, mid+1, end)
            self.tree[node] = self.tree[2*node] + self.tree[2*node+1]

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